변압기

Problem 예제

Multiple Choice • Views 1379 • Comments 0 • Created at 2 years ago • Last Updated at 5 months ago

시험법

변압기

전압 3300[V], 무부하 전류 0.1[A], 철손 150[W]인 변압기의 자화 전류[A]는 대략 얼마인가?

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1

0.061

2

0.097

3

0.089

4

0.073

Solution

$I_c = \dfrac{P_{oc}}{V_{oc}} = \dfrac{150}{3300} = 0.04545$

$I_m = \sqrt{I_{oc}^2-I_c^2} = \sqrt{0.1^2-0.045^2} = 0.0893$

Correct answer 3

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